If f(x)= x^ 2 -1 x^ 2 +1 , for every real number x, then the minimum value of f
Mathematics · JEE Advanced · NTA Exams — Sets, Relations and Functions
If \(f(x)=\frac{x^{2}-1}{x^{2}+1}\), for every real number x, then the minimum value of f
- does not exist because f is unbounded
- is not attained even though f is bounded
- is equal to 1
- is equal to –1
Answer
(D) is equal to –1
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