Two blocks A and B are placed on a table and joined by a string (figure). The limiting…
Physics · JEE Advanced · NTA Exams — Laws of Motion
Two blocks A and B are placed on a table and joined by a string (figure). The limiting friction for both blocks is F. The tension in the string is T. The forces of friction acting on the blocks are FA and FB. An external horizontal force P = 3F/2 acts on A, directed away from B. Then
- \(F_{A}=F_{B}=T=\frac{3 F}{4}\)
- \(F_{A}=\frac{F}{2}, F_{B}=F, T=F\)
- \(F_{A}=F_{B}=3 \frac{F}{4}, T=0\)
- \(F_{A}=F_{,} F_{B}=T=\frac{F}{2}\)
Answer
(D) F_ A =F_ , F_ B =T= F 2
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