The emf and internal resistance of a cell are E and r respectively. It is connected…
Physics · Class 12 · CBSE — Current Electricity
The emf and internal resistance of a cell are E and r respectively. It is connected across an external resistance R = 2r. The potential drop across the terminals of the cell will be:
- \(\frac{E}{4}\)
- \(\frac{E}{2}\)
- \(\frac{2}{3}E\)
- \(\frac{E}{3}\)
Answer
(C) 2 3 E
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The resistance of a metal wire increases with increasing temperature on account of
- Kirchhoff's first rule I = 0 and second rule IR = E (where the symbols have their usual meanings) are…
- When the terminals of a cell are connected to a conductor of resistance R, an electric current flows through…
- If a wire of resistivity is stretched to double its length, then its new resistivity will:
- The number of electrons flowing through a conductor per second is 3.3 10 19 . The current flowing through the…
- The total power dissipated (in watt) in the circuit shown is
- A cell of constant emf is first connected to a resistance R 1 and then connected to a resistance R 2 . If…
- In a current-carrying conductor, the ratio of the electric field and the current density at a point is called:
More Current Electricity questions · Browse all practice questions