Equation of the circle which passes through the centre of the circle x 2 + y 2 + 8x + 10y…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
Equation of the circle which passes through the centre of the circle x2 + y2 + 8x + 10y – 7 = 0 and is concentric with the circle 2x2 + 2y2– 8x – 12y – 9 = 0 is
- x2 + y2 – 4x – 8y – 97 = 0
- x2 + y2 – 4x – 6y – 87 = 0
- x2 + y2 – 2x – 8y – 95 = 0
- None of these
Answer
(B) x 2 + y 2 – 4x – 6y – 87 = 0
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