If α and β are the roots of the quadratic equations, x^ 2 +x -2 =0, (0, 2 ) , then a ^ 12…
Mathematics · JEE Main · NTA Exams — Complex Numbers and Quadratic Equations
If α and β are the roots of the quadratic equations, \(x^{2}+x \sin \theta-2 \sin \theta=0, \theta \in\left(0, \frac{\pi}{2}\right)\), then \(\frac{\mathrm{a}^{12}+\beta^{12}}{\left(\mathrm{a}^{-12}+\beta^{-12}\right) \cdot(\mathrm{a}-\beta)^{24}}\) is equal to:
- \(\frac{2^{12}}{(\sin \theta-8)^{5}}\)
- \(\frac{2^{6}}{(\sin \theta+8)^{12}}\)
- \(\frac{2^{12}}{(\sin \theta+8)^{12}}\)
- \(\frac{2^{12}}{(\sin \theta-4)^{12}}\)
Answer
(C) 2^ 12 ( +8)^ 12
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