The domain of the function f (x) = ( 1 x -1 ) is :
Mathematics · JEE Advanced · NTA Exams — Sets, Relations and Functions
The domain of the function f (x) = \(\sqrt{\left(\frac{1}{\sin x}-1\right)}\) is :
- \(\left\{2 \mathrm{n} \pi, 2 \mathrm{n} \pi+\frac{\pi}{2}\right\},\)\(\forall\) n ∈ I
- (2nπ , (2n + 1)π ) \(\forall\) n ∈ I
- ((2n – 1)π , 2nπ) \(\forall\) n ∈ I
- None of the above
Answer
(B) (2n π , (2n + 1) π ) n ∈ I
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