A transistor connected in common emitter configuration has input resistance R CE = 2Ω and…
Physics · JEE Main · NTA Exams — Electronic Devices
A transistor connected in common emitter configuration has input resistance RCE = 2Ω and load resistance of 5 kΩ. If β = 60 and an input signal 12 mV is applied, calculate the voltage gain, the power gain and the value of output voltage.


- AV = 150, Vout = 1.8 V, and power gain = 9000
- AV = 20, Vout = 1 V, and power gain = 2000
- AV = 150, Vout = 1.5 V, and power gain = 8500
- AV = 20, Vout = 1.5 V, and power gain = 2000
Answer
(A) A V = 150, V out = 1.8 V, and power gain = 9000
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Output Y is given by :
- When the forward bias voltage of a diode is changed from 0.6 V to 0.7 V the current changes from 5 mA to 15…
- Acceptor atoms introduced into a pure semiconductor at room temperature :
- Current in the circuit shown here is (assume diodes are ideal):
- A sinusoidal voltage of peak value 200 V is connected to a diode and resistor R in the cirucuit shown so that…
- The following configuration of gate is equivalent to :
- Carbon is more resistive than germanium and silicon. Then, order of energy gap is :
- In an n-p-n transistor circuit, the collector current is 9 mA. If 90% of the electrons emitted reach the…
More Electronic Devices questions · Browse all practice questions