The least value of cos 2 θ – (6 sin θ . cos θ) + 3 sin 2 θ + 2 is
Mathematics · JEE Advanced · NTA Exams — Trigonometry
The least value of cos2 θ – (6 sin θ . cos θ) + 3 sin2θ + 2 is
- \(4+\sqrt{10}\)
- \(4-\sqrt{10}\)
- 0
- 4
Answer
(B) 4- 10
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