A long string having a cross-sectional area 0.80 mm 2 and density 12.5 g/cm 3 is…

Physics · JEE Advanced · NTA ExamsOscillations and Waves


A long string having a cross-sectional area 0.80 mm2 and density 12.5 g/cm3 is subjected to a tension of 64 N along the x-axis. One end (at x = 0) of this string is attached to a vibrator moving in transverse direction at a frequency of 20 Hz.
At, t = 0, the source is at a maximum displacement y = 1.0cm.
 Write the equation for the wave.
  1. y = (1.0 cm) cos [(40 s–1) t – {(/2m–1) x}]
  2. y = (1.0 cm) cos [(40 s–1) t + {(/2m–1) x}]
  3. y = (1.0 cm) cos [(40 s–1) t – {(/4m–1) x}]
  4. y = (1.0 cm) cos [(40 s–1)t + {(/4m–1)x}]

Answer

(A) y = (1.0 cm) cos [(40  s–1) t – (  /2m–1) x ]

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