_ 0 ^ 2 [x^ 2 ] d x where [ . ] is GIF is :
Mathematics · JEE Main · NTA Exams — Integral Calculus
\(\int_{0}^{\sqrt{2}}\left[x^{2}\right] d x\) where [ . ] is GIF is :
- \(2-\sqrt{2}\)
- \(2+\sqrt{2}\)
- \(\sqrt{2}-1\)
- \(\sqrt{2}-2\)
Answer
(C) 2 -1
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