If x 2 + y 2 = t + 1 t and x 4 + y 4 = t 2 + 1 t ^ 2 , then dy dx is equal to
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
If x2 + y2 = t + \(\frac{1}{t}\) and x4 + y4 = t2 + \(\frac{1}{\mathrm{t}^{2}}\), then \(\frac{\mathrm{dy}}{\mathrm{dx}}\) is equal to
- \(\frac{y}{x}\)
- –\(\frac{y}{x}\)
- \(\frac{x}{y}\)
- –\(\frac{x}{y}\)
Answer
(B) – y x
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