The eccentricity of the ellipse 25 x^ 2 +16 y^ 2 -150 x-175=0 is,
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The eccentricity of the ellipse \(25 x^{2}+16 y^{2}-150 x-175=0\) is,
- \(\frac{2}{5}\)
- \(\frac{2}{3}\)
- \(\frac{3}{5}\)
- \(\frac{3}{4}\)
Answer
(B) 2 3
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