Four simple harmonic motions. x1 = 8 sin ωt; x2 = 6 sin (ωt + π/2); x3 = 4 sin (ωt + π)…
Physics · JEE Main · NTA Exams — Oscillations and Waves
Four simple harmonic motions.
x1 = 8 sin ωt; x2 = 6 sin (ωt + π/2); x3 = 4 sin (ωt + π) and x4 = 2 sin (ωt + 3π/2) are superimposed on each other. The resulting amplitude and its phase difference with x1 are respectively
x1 = 8 sin ωt; x2 = 6 sin (ωt + π/2); x3 = 4 sin (ωt + π) and x4 = 2 sin (ωt + 3π/2) are superimposed on each other. The resulting amplitude and its phase difference with x1 are respectively
- 20, tan–1 (1/2)
- 4\(\sqrt{2}\), /2
- 20, tan–1 (2)
- 4\(\sqrt{2}\), /4
Answer
(D) 4 2 , /4
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