A whistle producing sound waves of frequencies 9500 Hz and above is approaching a…
Physics · JEE Main · NTA Exams — Oscillations and Waves
A whistle producing sound waves of frequencies 9500 Hz and above is approaching a stationary person with speed v m/s. The velocity of sound in air is 300 m/s. If the person can hear frequencies up to a maximum of 10,000 Hz, the maximum value of v up to which he can hear the whistle is:
- \(15 / \sqrt{2}\) m/s
- 15 m/s
- 30 m/s
- \(15 \sqrt{2}\)m/s
Answer
(B) 15 m/s
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