A particle of charge +q and mass m moving under the influence of a uniform electric field…
Physics · JEE Advanced · NTA Exams — Magnetic Effects of Current and Magnetism
A particle of charge +q and mass m moving under the influence of a uniform electric field \(\mathrm{E} \hat{\mathrm{i}}\) and uniform magnetic field \(\mathrm{B} \hat{k}\) follows a trajectory from P to Q as shown in figure. The velocities at P and Q are \(v \hat{i}\) and \(-2 v \hat{j}\). Which of the following statement(s) is/are correct ?


- \(\mathrm{E}=\frac{3}{4}\left[\frac{\mathrm{mv}^{2}}{\mathrm{qa}}\right]\)
- Rate of work done by the electric field at P is \(\frac{3}{4}\left[\frac{\mathrm{mv}^{3}}{\mathrm{a}}\right]\)
- Rate of work done by the electric field at P is zero
- Rate of work done by both the fields at Q is zero
Answer
(A) E = 3 4 [ mv ^ 2 qa ], (B) Rate of work done by the electric field at P is 3 4 [ mv ^ 3 a ], (D) Rate of work done by both the fields at Q is zero
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