In the reaction : Cu (s) + 2Ag + (aq) → Cu 2+ (aq) + 2Ag (s) the reduction half cell…
Chemistry · JEE Advanced · NTA Exams — Electrochemistry
In the reaction :
Cu(s) + 2Ag+(aq) \(\text { → }\) Cu2+(aq) + 2Ag(s)
the reduction half cell reaction is
Cu(s) + 2Ag+(aq) \(\text { → }\) Cu2+(aq) + 2Ag(s)
the reduction half cell reaction is
- Cu + 2e– \(\text { → }\)Cu2+
- Cu – 2e– \(\text { → }\) Cu2+
- Ag+ + e– \(\text { → }\) Ag
- Ag – e– \(\text { → }\) Ag+
Answer
(C) Ag + + e – → Ag
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