If I_ n = _ 1 ^ E ( x)^ n d x , then I_ n +n I_ n-1 is
Mathematics · JEE Main · NTA Exams — Integral Calculus
If \(I_{n}=\int_{1}^{\mathrm{E}}(\log x)^{n} d x\), then \(I_{n}+n I_{n-1}\) is
- \(\frac{1}{\mathbf{e}}\)
- e
- e - 1
- None of these
Answer
(D) None of these
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