From the focus of the parabola, y 2 = 8x as centre, a circle is described so that a…
Mathematics · JEE Advanced · NTA Exams — Co-ordinate Geometry
From the focus of the parabola, y2 = 8x as centre, a circle is described so that a common chord of the curves is equidistant from the vertex & focus of the parabola. The equation of the circle is :
- (x – 2)2 + y2 = 9
- (x – 2)2 + y2 = 6
- (x – 2)2 + y2 = 4
- (x – 2)2 + y2 = 18
Answer
(A) (x – 2) 2 + y 2 = 9
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