Solubility of calcium phosphate (molecular mass, M) in water is W g per 100 mL at 25ºC…
Chemistry · JEE Advanced · NTA Exams — Equilibrium
Solubility of calcium phosphate (molecular mass, M) in water is W g per 100 mL at 25ºC. Its solubility product at 25ºC will be approximately :
- \(10^{9}\left(\frac{\mathrm{~W}}{\mathrm{M}}\right)^{5}\)
- \(10^{7}\left(\frac{\mathrm{~W}}{\mathrm{M}}\right)^{5}\)
- \(10^{5}\left(\frac{\mathrm{~W}}{\mathrm{M}}\right)^{5}\)
- \(10^{3}\left(\frac{\mathrm{~W}}{\mathrm{M}}\right)^{5}\)
Answer
(B) 10^ 7 ( ~W M )^ 5
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