The number of moles of K 2 Cr 2 O 7 reduced by one mole of Sn 2+ ions is
Chemistry · Class 11 · CBSE — Redox Reactions
The number of moles of K2Cr2O7 reduced by one mole of Sn2+ ions is
- 1/3
- 1/6
- 2/3
- 3/4
Answer
(A) 1/3
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Which type of redox reaction is shown by the following reaction?
- Identify the redox reaction taking place in a beaker.
- In which of the following compounds carbon is in highest oxidation state?
- The correct sequence of the oxidation state of underlined elements is Na 2 [ Fe (CN) 5 NO], K 2 Ta F 7 , Mg 2…
- In the reaction : 3Br 2 + 6CO 3 2– + 3H 2 O → 5Br – + BrO 3 – + 6HCO 3 –
- Which of the following is a decreasing order of oxidation states of the central atoms?
- Which species is acting as a reducing agent in the following reaction? 14H + + Cr 2 O 7 2– + 3Ni → 2Cr 3+ +…
- In which of the following reactions, the underlined substance has been reduced?
More Redox Reactions questions · Browse all practice questions