The equilibrium constant for this reaction is approximately 10 –3 . HPO _ 4 ^ 2- (aq.) +…

Chemistry · JEE Advanced · NTA ExamsEquilibrium

The equilibrium constant for this reaction is approximately 10–3.
\(\mathrm{HPO}_{4}^{2-} \text { (aq.) }+\mathrm{HCO}_{3}^{-} \text {(aq.) } \rightleftharpoons \mathrm{H}_{2} \mathrm{PO}_{4}^{-} \text {(aq.) }+\mathrm{CO}_{3}^{2-} \text { (aq.) }\)
Which is the strongest conjugate base in this reaction ?
  1. \(\mathrm{HPO}_{4}^{2-} \text { (aq.) }\)
  2. \(\mathrm{HCO}_{3}^{-} \text {(aq.) }\)
  3. \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-} \text {(aq.) }\)
  4. \(\mathrm{CO}_{3}^{2-} \text { (aq.) }\)

Answer

(D) CO _ 3 ^ 2- (aq.)

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