Molarity equation of a mixture of solutions of same substance is given by
Chemistry · Class 11 · CBSE — Some Basic Concepts of Chemistry
Molarity equation of a mixture of solutions of same substance is given by
- M1 + V1 × M2 + V2 × M3 + V3 + … = M1 + M2 + M3
- M1V1 + M2V2 + M3V3 + … = M(V1 + V2 + V3)
- \(\frac{M_{1}}{V_{1}}+\frac{M_{2}}{V_{2}}+\frac{M_{3}}{V_{3}}+\ldots=M\left(\frac{1}{V_{1}}+\frac{1}{V_{2}}+\frac{1}{V_{3}}\right)\)
- \(\frac{M_{1}}{V_{1}} \times \frac{M_{2}}{V_{2}} \times \frac{M_{3}}{V_{3}}+\ldots=M_{1}\left(\frac{1}{V_{1}} \times \frac{1}{V_{2}} \times \frac{1}{V_{3}}\right)\)
Answer
(B) M 1 V 1 + M 2 V 2 + M 3 V 3 + … = M ( V 1 + V 2 + V 3 )
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