Equation of plane which passes through the point of intersection of lines x-1 3 = y-2 1 =…
Mathematics · JEE Advanced · NTA Exams — Three Dimensional Geometry
Equation of plane which passes through the point of intersection of lines \(\frac{x-1}{3}=\frac{y-2}{1}=\frac{z-3}{2}\) and \(\frac{x-3}{1}\)\(=\frac{y-1}{2}=\frac{z-2}{3}\) and at greatest distance from the point (0, 0, 0) is :
- 4x + 3y + 5z = 25
- 4x + 3y + 5z = 50
- 3x + 4y + 5z = 49
- x + 7y – 5z = 2
Answer
(B) 4x + 3y + 5z = 50
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