In the hydrocarbon, H _ 3 C - 5 C H = 4 C H - 3 CH _ 2 - 2 C 1 C H The state of…
Chemistry · JEE Main · NTA Exams — Some Basic Principles of Organic Chemistry
In the hydrocarbon,
\(\mathrm{H}_{3} \mathrm{C}-\underset{5}{\mathrm{C}} \mathrm{H}=\underset{4}{\mathrm{C}} \mathrm{H}-\underset{3}{\mathrm{CH}_{2}}-\underset{2}{\mathrm{C}} \equiv \underset{1}{\mathrm{C}} \mathrm{H}\)
The state of hybridization of carbons 1,3,5 are in the following sequence :
\(\mathrm{H}_{3} \mathrm{C}-\underset{5}{\mathrm{C}} \mathrm{H}=\underset{4}{\mathrm{C}} \mathrm{H}-\underset{3}{\mathrm{CH}_{2}}-\underset{2}{\mathrm{C}} \equiv \underset{1}{\mathrm{C}} \mathrm{H}\)
The state of hybridization of carbons 1,3,5 are in the following sequence :
- sp, sp2, sp3
- sp3, sp2, sp
- sp2, sp, sp3
- sp, sp3, sp2
Answer
(D) sp, sp 3 , sp 2
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