Two bodies of masses m and M are placed a distance d apart. The gravitational potential…
Physics · JEE Advanced · NTA Exams — Gravitation
Two bodies of masses m and M are placed a distance d apart. The gravitational potential at the position where the gravitational field due to them is zero is V, then
- \(V=-\frac{G}{d}(m+M)\)
- \(V=-\frac{G m}{d}\)
- \(V=-\frac{G M}{d}\)
- \(y=-\frac{G}{d}(\sqrt{m}+\sqrt{M})^{2}\)
Answer
(D) y=- G d ( m + M )^ 2
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