A uniform metal rod of length 1 m is bent at 90° so as to form two arms of equal length…

Physics · JEE Main · NTA Exams — Laws of Motion

A uniform metal rod of length 1 m is bent at 90° so as to form two arms of equal length. The centre of mass of this bent rod is :

on the bisector of the angle, \(\left(\frac{1}{\sqrt{2}}\right)\) m from vertex
on the bisector of the angle,\(\left(\frac{1}{2 \sqrt{2}}\right)\) m from vertex
on the bisector of the angle,\(\left(\frac{1}{2}\right)\)m from vertex
on the bisector of the angle, \(\left(\frac{1}{4 \sqrt{2}}\right)\) m from vertex

Answer

(D) on the bisector of the angle, ( 1 4 2 ) m from vertex

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