The motion of a particle executing SHM is given as x=0.01 [100 (t+0.0005)] where, x is…
Physics · JEE Main · NTA Exams — Oscillations and Waves
The motion of a particle executing SHM is given as
\(x=0.01 \sin [100 \pi(t+0.0005)]\)
where, x is displacement in meter and t is time in seconds. Then the time-period is
- 0.01
- 0.02
- 0.10
- 0.20
Answer
(B) 0.02
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