If n N and (1 – x + x 2 ) n = a 0 + a 1 x + a 2 x 2 + ...... + a 2n x 2n , then a 0 + a 2…
Mathematics · JEE Main · NTA Exams — Binomial Theorem And Its Simple Applications
If n \(\epsilon\)N and (1 – x + x2)n = a0 + a1x + a2x2 + ...... + a2nx2n, then a0+ a2+ a4 + ... +a2n is equal to :
- \(\frac{3^{\mathrm{n}}+1}{2}\)
- \(\frac{3^{\mathrm{n}}-1}{2}\)
- \(3^{n}-\frac{1}{2}\)
- \(3^{n}+\frac{1}{2}\)
Answer
(A) 3^ n +1 2
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