The half cell reactions for rusting of iron are : Cathode: 2 H _ ( aq ) ^ + +2 e ^ - + 1…

The half cell reactions for rusting of iron are :
Cathode:
\(2 \mathrm{H}_{(\mathrm{aq})}^{+}+2 \mathrm{e}^{-}+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g}) \rightarrow \mathrm{H}_{2} \mathrm{O}(1) ; \mathrm{E}^{0}=+1.23 \mathrm{~V}\)
\(\text { Anode : } \mathrm{Fe}_{(\mathrm{s})} \rightarrow \mathrm{Fe}_{(\mathrm{aq})}^{+2}+2 \mathrm{e}^{-}\); \(\mathrm{E}^{0}=-0.44 \mathrm{~V}\) 
The ∆Gº (in kJ) for the reaction is (2005)