The value of θ lying between θ = 0 and = 2 and satisfying the equation | array ccc 1+ ^ 2…
Mathematics · JEE Advanced · NTA Exams — Matrices and Determinants
The value of θ lying between θ = 0 and \(\theta=\frac{\pi}{2}\) and satisfying the equation
\[\left|\begin{array}{ccc} 1+\sin ^{2} \theta & \cos ^{2} \theta & 4 \sin 4 \theta \\ \sin ^{2} \theta & 1+\cos ^{2} \theta & 4 \sin 4 \theta \\ \sin ^{2} \theta & \cos ^{2} \theta & 1+4 \sin 4 \theta \end{array}\right|=0 \text { are }\]
\[\left|\begin{array}{ccc} 1+\sin ^{2} \theta & \cos ^{2} \theta & 4 \sin 4 \theta \\ \sin ^{2} \theta & 1+\cos ^{2} \theta & 4 \sin 4 \theta \\ \sin ^{2} \theta & \cos ^{2} \theta & 1+4 \sin 4 \theta \end{array}\right|=0 \text { are }\]
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