The ionization potential of hydrogen is 13.6 eV. Then the energy released when an…
Chemistry · NEET · NTA Exams — Structure of Atom
The ionization potential of hydrogen is 13.6 eV. Then the energy released when an electron jumps from n = 3 to n = 2 orbit is:
- 2.89 eV
- 1.89 eV
- 3.89 eV
- 4.89 eV
Answer
(B) 1.89 eV
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A particle is moving 5 times as fast as an electron. The ratio of the de-Broglie wavelength of the particle…
- Light of frequency 1.5 times the threshold frequency is incident on a photosensitive material. If the…
- The total energy of an electron in the first excited state of hydrogen is about — 3.4 eV. Its kinetic energy…
- Two identical metal plates show photoelectric effect. Light of wavelength λ A falls on plate A and λ B falls…
- The threshold wavelength for photoelectrons emission from a material is 5200 a a Photoelectrons will be…
- Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R)…
- A particle of mass M at rest decay into two particles of masses m 1 and m 2 having non-zero velocities. The…
- The maximum kinetic energy of the emitted photoelectrons in photoelectric effect is independent of:
More Structure of Atom questions · Browse all practice questions