If a quantity A= K x^ -2 where K is constant and another quantity A= d B d x then find…
Physics · NEET · NTA Exams — Basic Mathematics for Physics
If a quantity \(A=\frac{K}{x^{-2}}\) where K is constant and another quantity \(A=\frac{d B}{d x}\) then find the formula for B.
- \(\frac{K x^{3}}{3}+C\)
- \(\frac{K x^{3}}{2}+c\)
- \(\frac{K^{2} x^{3}}{3}+c\)
- \(\frac{K x^{3}}{5}+c\)
Answer
(A) K x^ 3 3 +C
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- What will be the correct increasing order of 10^ , 70^ , 67 and 90 .
- What will be the value of 4 5 radian in degree?
- A particle starting from the origin (0, 0) moves in a straight line in the plane. Its coordinates at a later…
- Find the value of 1 ^ 2 + 1 cosec ^ 2
- If 1- 1+ = 3 , then find the value of .
- Find the slope of the line joining the points (7, 5) and (9, 11).
- Two rods (one semi-circular and other straight) of same material and of same cross-sectional area are joined…
- Find the value of ( 4 +i 4 )^ 4
More Basic Mathematics for Physics questions · Browse all practice questions