[ X ] + H 2 SO 4 → [ Y ] a colourless gas with irritating smell, [ Y ] + K 2 Cr 2 O 7 + H…
Chemistry · JEE Advanced · NTA Exams — Chemical Bonding and Molecular Structure
[X] + H2SO4 → [Y] a colourless gas with irritating smell, [Y] + K2Cr2O7 + H2SO4 → green solution.
[X] and [Y] are
[X] and [Y] are
- SO32–, SO2
- Cl–, HCl
- S2–, H2S
- CO32–, CO2
Answer
(A) SO 3 2– , SO 2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Which one among the following does not have the hydrogen bond ? (1983)
- Which is correct statements ? As the s-character of a hybrid orbital decreases (I) The bond angle decreases…
- The state of hybridisation of central atom in dimer of BH 3 and BeH 2 is :
- The geometry of H 2 S and its dipole moment are
- Molecular shapes of SF 4 , CF 4 and XeF 4 are (2000)
- Assuming 2 s -2 p mixing is not operative, the paramagnetic species among the following is
- The geometry with respect to the central atom of the following molecules are : N (SiH 3 ) 3 ; Me 3 N ; (SiH 3…
- Amongst H 2 O, H 2 S, H 2 Se and H 2 Te, the one with the highest boiling point is
More Chemical Bonding and Molecular Structure questions · Browse all practice questions