If a , b , c are three non-zero non-coplanar vectors and b _ 1 = b - a b | a |^ 2 a , b _…

Physics · JEE Advanced · NTA ExamsKinematics

If \(\vec{a}, \vec{b}, \vec{c}\)are three non-zero non-coplanar vectors and
\(\vec{b}_{1}=\vec{b}-\frac{\vec{a} \cdot \vec{b}}{|\vec{a}|^{2}} \vec{a}, \vec{b}_{2}=\vec{b}+\frac{\vec{a} \cdot \vec{b}}{|\vec{a}|^{2}} \vec{a}\)
\(\vec{c}_{1}=\vec{c}-\frac{\vec{c} \cdot \vec{a}}{|\vec{a}|^{2}} \vec{a}-\frac{\vec{b} \cdot \vec{c}^{2}}{|\vec{c}|^{2}} \vec{b}_{1},\) \(\vec{c}_{2}=\vec{c}-\frac{\vec{c} \cdot \vec{a}}{|\vec{a}|^{2}} \vec{a}-\frac{\vec{b}_{1} \cdot \vec{c}^{2}}{\left|\vec{b}_{1}\right|^{2}} \vec{b}_{1}\)
\(\vec{c}_{3}=\vec{c}-\frac{\vec{c} \cdot \vec{a}}{|\vec{c}|^{2}} \vec{a}+\frac{\vec{b} \cdot \vec{c}}{|\vec{c}|^{2}} \vec{b}_{1},\) \(\vec{c}_{4}=\vec{c}-\frac{\vec{c} \cdot \vec{a}}{|\vec{c}|^{2}} \vec{a}-\frac{\vec{b} \cdot \vec{c}}{|\vec{b}|^{2}} \vec{b}_{1},\)
then the set of orthogonal vectors is

Answer

(B)

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