A library has ‘a’ copies of one book, ‘b’ copies of each of two books, ‘c’ copies of each…
Mathematics · JEE Main · NTA Exams — Permutations and Combinations
A library has ‘a’ copies of one book, ‘b’ copies of each of two books, ‘c’ copies of each of three books, and single copy each of ‘d’ books. The total number of ways in which these books can be arranged in a row is
- \(\frac{(a+b+c+d)!}{a!b!c!}\)
- \(\frac{(a+2 b+3 c+d)!}{a!(b!)^{2}(c!)^{3}}\)
- \(\frac{(a+2 b+3 c+d)!}{a!b!c!}\)
- none of these
Answer
(B) (a+2 b+3 c+d)! a!(b!)^ 2 (c!)^ 3
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