The radius of curvature for a convex lens is 40 cm, for each surface. Its refractive…
Physics · JEE Main · NTA Exams — Optics
The radius of curvature for a convex lens is 40 cm, for each surface. Its refractive index is 1.5 . The focal length will be
- 40 cm
- 20 cm
- 80 cm
- 30 cm
Answer
(A) 40 cm
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A 2.0 cm object is placed 15 cm in front of a concave mirror of focal length 10 cm. What is the size and…
- The size of the image of an object, which is at infinity, as formed by a convex lens of focal length 30cm is…
- In the YDSE shown the two slits are covered with thin sheets having thickness t & 2t and refractive index 2…
- If two lenses of +5 diopters are mounted at some distance apart, the equivalent power will always be negative…
- Two transparent media A and B are separated by a plane boundary. The speed of light in medium A is 2.0 10^ 8…
- A convex lens of focal length f is put in contact with a concave lens of same focal length. The focal length…
- In a YDSE experiment if a slab whose refractive index can be varied is placed in front of one of the slits…
- A concave and convex lens have same focal length of 20 cm and are put in contact. The combination is used to…