For the cell :- 2Ag + Pt 2+ → 2Ag + + Pt Eº = 0.4 volt 2Ag + F 2 → 2Ag + + 2F – Eº = 2.07…
Chemistry · JEE Advanced · NTA Exams — Electrochemistry
For the cell :-
2Ag + Pt2+ \(\text { → }\) 2Ag+ + Pt Eº = 0.4 volt
2Ag + F2 \(\text { → }\) 2Ag+ + 2F– Eº = 2.07 volt
If the potential for the reaction Pt \(\text { → }\) Pt2+ + 2e– is assigned zero. Then
2Ag + Pt2+ \(\text { → }\) 2Ag+ + Pt Eº = 0.4 volt
2Ag + F2 \(\text { → }\) 2Ag+ + 2F– Eº = 2.07 volt
If the potential for the reaction Pt \(\text { → }\) Pt2+ + 2e– is assigned zero. Then
- \(\mathrm{E}_{\mathrm{Ag}^{2} / \mathrm{Ag}^{+}}=-0.4 \mathrm{~V}\)
- \(\mathrm{E}_{\mathrm{Ag}^{+} / \mathrm{Ag}}^{\circ}=0.4 \mathrm{~V}\)
- \(\mathrm{E}_{\mathrm{F}_{2} / \mathrm{F}^{-}}^{\circ}=1.67 \mathrm{~V}\)
- \(\mathrm{E}_{\mathrm{F}_{2} / \mathrm{F}^{-}}^{\circ}=2.74 \mathrm{~V}\)
Answer
(C) E _ F _ 2 / F ^ - ^ =1.67 ~V
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