The function f(x)= [ (x+ 1+x^ 2 ) ] is
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
The function \(f(x)=\sec \left[\log \left(x+\sqrt{1+x^{2}}\right)\right] \text { is }\)
- odd
- even
- neither odd nor even
- constant
Answer
(A) odd
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