The number of electrons in Na(11) having l = 0 are equal to
Chemistry · JEE Advanced · NTA Exams — Atomic Structure
The number of electrons in Na(11) having l = 0 are
equal to
equal to
- there are two electrons in 1s orbital.
- there are two electrons in 2s orbital.
- there are two electrons in 2p orbital.
- there are one electrons in 3s orbital.
Answer
(A) there are two electrons in 1 s orbital., (B) there are two electrons in 2 s orbital., (D) there are one electrons in 3 s orbital.
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