If f (x) = |x –1| and g (x) = f [ f f (x) ], then for x >2, g ’ (x) is equal to
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
If f (x) = |x –1| and g (x) = f [f { f (x) }], then for x >2, g’ (x) is equal to
- –1 if 2 < x < 3
- 1 if 2 < x < 3
- 1 for all x > 2
- None of these
Answer
(A) –1 if 2 < x < 3
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The function f ( x ) = sin 4 x + cos 4 x increases if
- If _ x 0 x(1+a x)-b x x^ 3 =1, then
- The value of a for which _ x 0 (e^ x -1 )^ 4 ( x^ 2 a^ 2 ) _ e 1+ x^ 2 2 =8, is
- _ x 0 x 2 x-2 x x (1- 2 x)^ 2 is
- Let g ( x ) = x f ( x ), where f(x)= array cl x 1 x , & x 0 0, & x=0 array . At x=0 .
- Consider two functions f (x) = _ n ( x n )^ n and g(x) = –x 4b where b = _ x ( x^ 2 +x+1 - x^ 2 +1 ) Then…
- Let f : R → R be a differentiable function and f (1) = 4. Then the value of _ x 1 1 x-1 _ 4 ^ f(x) 2 t d t is
- The smallest positive root of the equation, tan x – x = 0 lies in
More Limit, Continuity and Differentiability questions · Browse all practice questions