A body of mass M is taken from the surface of the Earth to a height equal to the radius…
Physics · NEET · NTA Exams — Gravitation
A body of mass M is taken from the surface of the Earth to a height equal to the radius of the Earth. The subsequent change in the gravitational potential energy is
- \(\frac{\mathrm{MgR}}{4}\)
- \(\frac{\mathrm{MgR}}{2}\)
- \(\mathrm{MgR}\)
- \(2 \mathrm{MgR}\)
Answer
(B) MgR 2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The time-period of a satellite of the Earth is 5 hours. If the separation between the Earth and the satellite…
- The density of newly discovered planet is twice that of Earth. The acceleration due to gravity at the surface…
- According to Kepler's law the time period of a satellite varies with its radius as
- The kinetic energy needed to project a body of mass m from the Earth's surface (radius R) to infinity is
- The escape velocity on the surface of the Earth is 11.2 km/s. If mass and radius of a planet is 4 and 2…
- If a person with a spring balance and a body hanging from it goes up and up in an aeroplane, then the reading…
- The escape velocity from the Earth's surface is 11.2 km/s. A certain planet has a radius 2R, twice that of…
- Imagine a new planet having the same density as that of the Earth but it is 3 times bigger than the Earth in…