Calculate _ f G ^ for (NH 4 Cl, s) at 310 K. Given : _ f H ^ (NH 4 Cl, s)= –314.5 kJ/mol…
Chemistry · JEE Advanced · NTA Exams — Chemical Thermodynamics
Calculate \(\Delta_{f} \mathrm{G}^{\circ}\) for (NH4Cl, s) at 310 K.
Given :\(\Delta_{f} \mathrm{H}^{\circ}\)(NH4Cl, s)= –314.5 kJ/mol; \(\Delta_{r} C_{p}\)=0
\(\mathrm{S}_{\mathrm{N}_{2}(\mathrm{~g})}^{o}\)=192 JK–1 mol–1; \(\mathrm{S}_{\mathrm{H}_{2}(\mathrm{~g})}^{\circ}\)=130.5JK–1 mol–1
\(\mathrm{S}_{\mathrm{Cl}_{2}(\mathrm{~g})}^{\mathrm{o}}\)=233 JK–1 mol–1 \(\mathrm{S}_{\mathrm{NH}_{4} \mathrm{Cl}(\mathrm{~s})}^{o}\)= 99.5 JK–1 mol–1
(All data given at 300K)
Given :\(\Delta_{f} \mathrm{H}^{\circ}\)(NH4Cl, s)= –314.5 kJ/mol; \(\Delta_{r} C_{p}\)=0
\(\mathrm{S}_{\mathrm{N}_{2}(\mathrm{~g})}^{o}\)=192 JK–1 mol–1; \(\mathrm{S}_{\mathrm{H}_{2}(\mathrm{~g})}^{\circ}\)=130.5JK–1 mol–1
\(\mathrm{S}_{\mathrm{Cl}_{2}(\mathrm{~g})}^{\mathrm{o}}\)=233 JK–1 mol–1 \(\mathrm{S}_{\mathrm{NH}_{4} \mathrm{Cl}(\mathrm{~s})}^{o}\)= 99.5 JK–1 mol–1
(All data given at 300K)
- – 198.56 kJ/mol
- –426.7 KJ/mol
- –202.3 KJ/mol
- None of these
Answer
(A) – 198.56 kJ/mol
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