The oxidation states of sulphur in the anions; 50_ 3 ^ 2- , 5_ 2 0_ 4 ^ 2- , 5_ 2 0_ 6 ^…
Chemistry · NEET · NTA Exams — Some Basic Concepts of Chemistry
The oxidation states of sulphur in the anions; \(50_{3}^{2-}, 5_{2} 0_{4}^{2-}, 5_{2} 0_{6}^{2-}\) follow the order:
- \(\mathrm{S}_{2} \mathrm{O}_{4}^{2-}<\mathrm{S}_{2} \mathrm{O}_{6}^{2-}<5 \mathrm{O}_{3}^{2-}\)
- \(\mathrm{S}_{2} \mathrm{O}_{6}^{2-}<\mathrm{S}_{2} \mathrm{O}_{4}^{2-}<5 \mathrm{O}_{3}^{2-}\)
- \(5_{2} \mathrm{O}_{4}^{2-}<5 \mathrm{O}_{3}^{2-}<5_{2} \mathrm{O}_{6}^{2-}\)
- \(50_{3}^{2-}<5_{2} 0_{4}^{2-}<5_{2} 0_{6}^{2-}\)
Answer
(C) 5_ 2 O _ 4 ^ 2- <5 O _ 3 ^ 2- <5_ 2 O _ 6 ^ 2-
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