The mean kinetic energy of translation per gram molecule of a gas is
Physics · NEET · NTA Exams — KINETIC THEORY OF GASES
The mean kinetic energy of translation per gram molecule of a gas is
- \(\frac{1}{2} \mathrm{RT}\)
- \(\frac{3}{2} \mathrm{RT}\)
- \(\frac{5}{2} \text { RT }\)
- \(\frac{9}{2} \mathrm{RT}\)
Answer
(B) 3 2 RT
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