A uniform rod of length L has a mass per unit length λ and area of cross section A. The…
Physics · JEE Advanced · NTA Exams — Properties of Solids and Liquids
A uniform rod of length L has a mass per unit length λ and area of cross section A. The elongation in the rod is due to its own weight if it is suspended from the ceiling of a room. The Young’s modulus of the rod is
- \(\frac{2 \lambda \mathrm{gL}^{2}}{\mathrm{~A} \ell}\)
- \(\frac{\lambda \mathrm{gL}^{2}}{2 \mathrm{~A} \ell}\)
- \(\frac{2 \lambda \mathrm{gL}}{\mathrm{~A} \ell}\)
- \(\frac{\lambda \mathrm{g} \ell^{2}}{\mathrm{AL}}\)
Answer
(B) gL ^ 2 2 ~A
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