For the redox reaction : Zn (s) + Cu 2+ (0.1M) → Zn 2+ (1M) + Cu (s) taking place in a…
Chemistry · JEE Advanced · NTA Exams — Electrochemistry
For the redox reaction :
Zn (s) + Cu2+ (0.1M) \(\text { → }\) Zn2+ (1M) + Cu (s)
taking place in a cell, \(E_{\mathrm{cell}}^{o}\) is 1.10 volt. Ecell for the cell will be \(\left(2.303 \frac{\mathbb{R}}{F}=0.0591\right)\)
Zn (s) + Cu2+ (0.1M) \(\text { → }\) Zn2+ (1M) + Cu (s)
taking place in a cell, \(E_{\mathrm{cell}}^{o}\) is 1.10 volt. Ecell for the cell will be \(\left(2.303 \frac{\mathbb{R}}{F}=0.0591\right)\)
- 2.14 volt
- 1.80 volt
- 1.07 volt
- 0.82 volt
Answer
(C) 1.07 volt
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