An aqueous solution of metal ion M 1 reacts separately with reagents Q and R in excess to…
Chemistry · JEE Advanced · NTA Exams — Coordination Compounds
An aqueous solution of metal ion M1 reacts separately with reagents Q and R in excess to give tetrahedral and square planar complexes, respectively. An aqueous solution of another metal ion M2 always forms tetrahedral complexes with these reagents. Aqueous solution of M2 on reaction with reagent S gives white precipitate which dissolves in excess of S. The reactions are summarized in the scheme given below :
Scheme :
\[Tetrahedral \(\underset{\text { excess }}{\stackrel{Q}{\leftrightarrows}} M_{1} \underset{\text { excess }}{\stackrel{\mathrm{R}}{\leftrightarrows}}\) Square planar White precipitate \(\xrightarrow[\text { excess }]{S}\) precipitate dissolves\]
Reagent S is
- K4[Fe(CN)6]
- Na2HPO4
- K2CrO4
- KOH
Answer
(D) KOH
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