For the allotropic change represented by the equation C (diamond) → (graphite) the…
Chemistry · JEE Advanced · NTA Exams — Chemical Thermodynamics
For the allotropic change represented by the equation
C (diamond) → (graphite) the enthalpy change is
∆H = – 1.89 kJ
If 6g of diamond and 6 g of graphite are separately burnt to yield carbon dioxide, the heat, liberated in the first case is
C (diamond) → (graphite) the enthalpy change is
∆H = – 1.89 kJ
If 6g of diamond and 6 g of graphite are separately burnt to yield carbon dioxide, the heat, liberated in the first case is
- less than in the second case by 1.89 kJ
- more than in the second case by 1.89 kJ
- less than in the second case by 11.34 kJ
- more than in the second case by 0.945 kJ
Answer
(D) more than in the second case by 0.945 kJ
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