For the hypothetical reaction A 2 + B 2 ⟶ 2AB, the mechanism is given as below A 2 A +…

Chemistry · JEE Advanced · NTA Exams — Chemical Kinetics

For the hypothetical reaction
A₂ + B₂ \(\text { ⟶ }\) 2AB, the mechanism is given as below
A₂ A + A(fast reaction)
A + B₂ \(\text { ⟶ }\) AB + B (slow reaction)
A + B \(\text { ⟶ }\) AB (fast reaction)
then

1. the rate determining step is A + B₂ \(\text { ⟶ }\) AB + B
2. the order of the reaction is 3/2
3. the overall molecularity is 4
4. the rate expression is Rate = k [A] [B₂]

Answer

(A) the rate determining step is A + B 2 ⟶ AB + B, (B) the order of the reaction is 3/2

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