A solid sphere is rolling on a frictionless surface, shown in figure with a translational…
Physics · JEE Main · NTA Exams — Rotational Motion
A solid sphere is rolling on a frictionless surface, shown in figure with a translational velocity v m/s. If it is to climb the inclined surface then v should be:
- \(\geq \sqrt{\frac{10}{7} g h}\)
- \(\geq \sqrt{2 g h}\)
- 2gh
- \(\frac{10}{7} g h\)
Answer
(B) 2 g h
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